2y^4-3y^2-35=

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Solution for 2y^4-3y^2-35= equation: 


Simplifying
2y4 + -3y2 + -35 = 0

Reorder the terms:
-35 + -3y2 + 2y4 = 0

Solving
-35 + -3y2 + 2y4 = 0

Solving for variable 'y'.

Factor a trinomial.
(-7 + -2y2)(5 + -1y2) = 0


Subproblem 1
Set the factor '(-7 + -2y2)' equal to zero and attempt to solve:

Simplifying
-7 + -2y2 = 0

Solving
-7 + -2y2 = 0

Move all terms containing y to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -2y2 = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -2y2 = 0 + 7
-2y2 = 0 + 7

Combine like terms: 0 + 7 = 7
-2y2 = 7

Divide each side by '-2'.
y2 = -3.5

Simplifying
y2 = -3.5

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Subproblem 2
Set the factor '(5 + -1y2)' equal to zero and attempt to solve:

Simplifying
5 + -1y2 = 0

Solving
5 + -1y2 = 0

Move all terms containing y to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1y2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1y2 = 0 + -5
-1y2 = 0 + -5

Combine like terms: 0 + -5 = -5
-1y2 = -5

Divide each side by '-1'.
y2 = 5

Simplifying
y2 = 5

Take the square root of each side:
y = {-2.236067978, 2.236067978}
Solution
y = {-2.236067978, 2.236067978}

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